提问者:小点点

无法读取未定义cloudinary的属性“buffer”


我有这个错误

TypeError[ERR_INVALID_ARG_TYPE]:“chunk”参数必须是string类型或Buffer实例。接收到Object的实例

但我不知道怎么解决:

下面是我的代码库:

router.post('/upload/image', fileUpload.single('file'), function (req, res, next) {
  let streamUpload = (req) => {
    return new Promise((resolve, reject) => {
      let stream = cloudinary.uploader.upload_stream(
        (error, result) => {
          if (result) {
            resolve(result);
          } else {
            reject(error);
          }
        }
      );
      console.log("Images ", req.files);  
      streamifier.createReadStream(req.files.buffer).pipe(stream);
    }).
      catch(error => { throw error; });
  };
  
  async function upload(req) {
      let result = await streamUpload(req);
      console.log(result);
  }
  
  upload(req);
});

谢谢任何帮助我解决这个问题的人


共2个答案

匿名用户

在使用fileupload.single(“file”)时,应该使用req.file而不是req.files

注意req.file.buffer只能与memorystorage一起使用

const storage = multer.memoryStorage();
cont upload = multer({ storage: storage });

https://www.npmjs.com/package/multer#memorystorage

console.log("Images ", req.file);  
streamifier.createReadStream(req.file.buffer).pipe(stream);

https://www.npmjs.com/package/multer

app.post('/profile', upload.single('avatar'), function (req, res, next) {
  // req.file is the `avatar` file
  // req.body will hold the text fields, if there were any
})

匿名用户

cloudinary.uploader.upload_stream需要两个参数,第一个应该是字符串缓冲区,第二个应该是回调对象(错误,结果)

您将(error,result)作为唯一的参数传递,我相信这就是导致错误的原因。

cloudinary.uploader.upload_stream('YOUR BUFFER OR STRING HERE', (error, result)=>{})