我正在努力找出最有效的方法来实现一系列目标，即对我的数据进行分组、汇总列以及根据汇总更改新列。
通过下面的示例数据，我想：
这篇文章接近于帮助我，但我不是想总结（跨越（））多列： dplyr：group_by，对各种列求和，并应用基于分组行和的函数？
你将如何在dplyr中使用管道从“df_have”到“df_want”？
谢谢你！
site <- c("X", "Y", "Y", "X", "X", "X", "Y", "X", "Y", "X", "Y", "Y", "X", "X", "X", "Y", "X", "Y")
trmt <- c("yes", "yes", "no", "no", "yes", "no", "no", "yes", "yes", "yes", "yes", "no", "no", "yes", "no", "no", "yes", "yes")
id <- c(1, 2, 3, 4, 5, 6, 7, 8, 9, 1, 2, 3, 4, 5, 6, 7, 8, 9)
species <- c("a", "b", "a", "c", "d", "a", "e", "b", "d", "a", "b", "m", "c", "p", "a", "q", "r", "d")
count <- c(28, 17, 7, 8, 2, 9, 1, 5, 3, 12, 4, 18, 3, 30, 12, 21, 18, 6)
extra <- c("A", "A", "A", "A", "A", "A", "A", "A", "B", "B", "B", "B", "B", "B", "B", "B", "B", "B")
df_have <- cbind(site, trmt, id, species, count, extra)
df_have <- as.data.frame(df_have)
df_have
site1 <- c("X", "Y", "Y", "X", "X", "Y", "Y", "X", "X", "Y" )
trmt1 <- c("yes", "yes", "no", "yes", "no", "no", "no", "yes", "yes", "yes" )
id1 <- c(1, 2, 3, 3, 4, 5, 5, 6, 7, 7, 8, 8, 9)
species1 <- c("a", "b", "a", "m", "c", "d", "p", "a", "e", "q", "b", "r", "d" )
sum <- c(40, 21, 7, 18, 11, 2, 30, 21, 1, 21, 5, 18, 9)
relabund <- c(100, 100, 38.9, 61.1, 100, 6.25, 93.75, 100, 4.54, 95.45, 27.74, 78.26, 100)
df_want <- cbind(site1, trmt1, id1, species1, sum, relabund)
df_want <- as.data.frame(df_want)
df_want
这是一个dplyr选项
library(dplyr)
df_have %>%
group_by(site, trmt, id, species) %>%
summarise(sum = sum(as.integer(count)), .groups = "drop") %>%
group_by(id) %>%
mutate(relabund = sum / sum(sum) * 100) %>%
ungroup() %>%
arrange(id, species)
## A tibble: 13 x 6
# site trmt id species sum relabund
# <chr> <chr> <chr> <chr> <int> <dbl>
# 1 X yes 1 a 40 100
# 2 Y yes 2 b 21 100
# 3 Y no 3 a 7 28
# 4 Y no 3 m 18 72
# 5 X no 4 c 11 100
# 6 X yes 5 d 2 6.25
# 7 X yes 5 p 30 93.8
# 8 X no 6 a 21 100
# 9 Y no 7 e 1 4.55
#10 Y no 7 q 21 95.5
#11 X yes 8 b 5 21.7
#12 X yes 8 r 18 78.3
#13 Y yes 9 d 9 100
最后一个安排（）命令只是为了匹配您的预期输出；如果顺序无关紧要，您可以省略。另请注意，count列中的数据是字符s，因此我们需要先转换为整数；这可能是上游应该修复的问题。
