我有两个Java应用程序。一个应用程序将包含资源文件，并将用作其他Java应用程序的库。

第一个应用程序com.test.resourceusing.MainClass.java包含res/base. xml资源文件。

package com.test.resourceusing;

import java.io.BufferedInputStream;
import java.io.File;

import java.net.MalformedURLException;
import java.net.URL;

import java.util.Scanner;

public class MainClass {
public MainClass() {
    super();
}

public static void main(String[] args) {
    MainClass main = new MainClass();
    try {
        main.start();
    } catch (MalformedURLException e) {
    }
}

public void start() throws MalformedURLException {
    URL url = getClass().getResource("res/base.xml");
    System.out.println(url.getPath());
    System.out.println(url.getFile());
    File f = new File(url.getFile());
    if (f.exists()) {
        System.out.println("File exist!");

        BufferedInputStream result = (BufferedInputStream) 
              getClass().getResourceAsStream("res/base.xml");
        Scanner scn = new Scanner(result);
        while(scn.hasNext()){
            System.out.println(scn.next());
        }
    } else {
        System.out.println("Not working! :(");    
    }
}

}

结果是：

/C:/Work/Projects/ResourceUsing/classes/com/test/resourceusing/res/base.xml
/C:/Work/Projects/ResourceUsing/classes/com/test/resourceusing/res/base.xml
File exist!
<?xml
version='1.0'
encoding='utf-8'?>
<schema>
</schema>

然后我创建。jar文件，其中包含所有资源文件，并尝试将其用作其他应用程序中的库。

第二个应用：resourcetest.MainClassTest.java

package resourcetest;

import com.test.resourceusing.MainClass;

import java.net.MalformedURLException;

public class MainClassTest {
  public MainClassTest() {
    super();
  }

  public static void main(String[] args) {
    MainClass main = new MainClass();
    try {
        main.start();
    } catch (MalformedURLException e) {
    }
  }
}

结果是：

file:/C:/Work/Projects/ResourceUsing/deploy/archive1.jar!/com/test/resourceusing/res/base.xml
file:/C:/Work/Projects/ResourceUsing/deploy/archive1.jar!/com/test/resourceusing/res/base.xml
Not working! :(

我不明白为什么它不起作用，是我的代码有问题吗？还是这个解决方案在Java是不可能的？