提问者:小点点

如何将DefaultMutableTreeNode(Java)序列化为JSON?


如何将树(使用 DefaultMutableTreeNode 类在 Java 中实现)序列化为 JSON(用于通过 RESTful 方法传输到 iOS 客户端)?

我试过:

String jsonString = (new Gson()).toJson(topNode);
// topNode is DefaultMutableTreeNode at the root

它崩溃了,出现了StackOverflowError


共2个答案

匿名用户

Swing的DefaultMutableTreeNode类是一个类似于树的数据结构,它包含与子级父级同一类型的实例。这就是为什么Gson的默认序列化程序遇到无限递归,因此抛出了一个<code>StackOverflowError</code>。

要解决此问题,您需要使用专门为将DefaultMutableTreeNode转换为JSON而设计的更智能的JsonSerializer自定义Gson。另外,您可能还希望提供一个<code>JsonDeserializer</code>,用于将此类JSON转换回<code>DefaultMutableTreeNode</code<。

为此,不仅通过newGson(),而且通过

Gson gson = new GsonBuilder()
        .registerTypeAdapter(DefaultMutableTreeNode.class, new DefaultMutableTreeNodeSerializer())
        .registerTypeAdapter(DefaultMutableTreeNode.class, new DefaultMutableTreeNodeDeserializer())
        .setPrettyPrinting()
        .create();

下面的DefaultMutableTreeNodeSerializer负责将DefaultMutabbleTreeNode转换为JSON。它将其财产allowsChildrenuserObjectchildren转换为JSON。注意,它不会将<code>父</code>属性转换为JSON,因为这样做会再次产生无限递归。

public class DefaultMutableTreeNodeSerializer implements JsonSerializer<DefaultMutableTreeNode> {

    @Override
    public JsonElement serialize(DefaultMutableTreeNode src, Type typeOfSrc, JsonSerializationContext context) {
        JsonObject jsonObject = new JsonObject();
        jsonObject.addProperty("allowsChildren", src.getAllowsChildren());
        jsonObject.add("userObject", context.serialize(src.getUserObject()));
        if (src.getChildCount() > 0) {
            jsonObject.add("children", context.serialize(Collections.list(src.children())));
        }
        return jsonObject;
    }
}

为了进行测试,让我们将示例 JTree 的根节点序列化为 JSON,然后再次反序列化。

JTree tree = new JTree();  // create a sample tree
Object topNode = tree.getModel().getRoot();  // a DefaultMutableTreeNode
String jsonString = gson.toJson(topNode);
System.out.println(jsonString);
DefaultMutableTreeNode topNode2 = gson.fromJson(jsonString, DefaultMutableTreeNode.class);

它生成以下JSON输出:

{
  "allowsChildren": true,
  "userObject": "JTree",
  "children": [
    {
      "allowsChildren": true,
      "userObject": "colors",
      "children": [
        {
          "allowsChildren": true,
          "userObject": "blue"
        },
        {
          "allowsChildren": true,
          "userObject": "violet"
        },
        {
          "allowsChildren": true,
          "userObject": "red"
        },
        {
          "allowsChildren": true,
          "userObject": "yellow"
        }
      ]
    },
    {
      "allowsChildren": true,
      "userObject": "sports",
      "children": [
        {
          "allowsChildren": true,
          "userObject": "basketball"
        },
        {
          "allowsChildren": true,
          "userObject": "soccer"
        },
        {
          "allowsChildren": true,
          "userObject": "football"
        },
        {
          "allowsChildren": true,
          "userObject": "hockey"
        }
      ]
    },
    {
      "allowsChildren": true,
      "userObject": "food",
      "children": [
        {
          "allowsChildren": true,
          "userObject": "hot dogs"
        },
        {
          "allowsChildren": true,
          "userObject": "pizza"
        },
        {
          "allowsChildren": true,
          "userObject": "ravioli"
        },
        {
          "allowsChildren": true,
          "userObject": "bananas"
        }
      ]
    }
  ]
}

下面的DefaultMutableTreeNodeDeserializer负责将JSON转换回DefaultMutableTreeNode

它使用了与How to serialize/deserialize a DefaultMutableTreeNode with Jackson?中的反序列化程序相同的思想?。DefaultMutableTreeNode不太像POJO,因此不能与Gson一起工作。因此,它使用了一个行为良好的POJO帮助器类(具有财产allowsChildrenuserObjectchildren),并让Gson将JSON内容反序列化到这个类中。然后,POJO对象(及其POJOchildren)被转换为DefaultMutableTreeNode子对象(具有DefaultMutabbleTreeNode子对象)。

public class DefaultMutableTreeNodeDeserializer implements JsonDeserializer<DefaultMutableTreeNode> {

    @Override
    public DefaultMutableTreeNode deserialize(JsonElement json, Type type, JsonDeserializationContext context) {
        return context.<POJO>deserialize(json, POJO.class).toDefaultMutableTreeNode();
    }

    private static class POJO {

        private boolean allowsChildren;
        private Object userObject;
        private List<POJO> children;
        // no need for: POJO parent

        public DefaultMutableTreeNode toDefaultMutableTreeNode() {
            DefaultMutableTreeNode node = new DefaultMutableTreeNode();
            node.setAllowsChildren(allowsChildren);
            node.setUserObject(userObject);
            if (children != null) {
                for (POJO child : children) {
                    node.add(child.toDefaultMutableTreeNode()); // recursion!
                    // this did also set the parent of the child-node
                }
            }
            return node;
        }

        // Following setters needed by Gson's deserialization:

        public void setAllowsChildren(boolean allowsChildren) {
            this.allowsChildren = allowsChildren;
        }

        public void setUserObject(Object userObject) {
            this.userObject = userObject;
        }

        public void setChildren(List<POJO> children) {
            this.children = children;
        }
    }
}

匿名用户

这是对我以前的答案的一个改进的替代方案,该答案使用JsonSerializerJRsonDeserializer实现DefaultMutableTreeNode。这两个接口的API文档表示:

新的应用程序应该更喜欢TypeAdapter,它的流API比这个接口的树API更高效。

因此,让我们使用这种首选方法,并为< code > DefaultMutableTreeNode 实现一个< code>TypeAdapter。

为了使用它,您可以像这样创建Gson实例(而不是只使用newGson()):

Gson gson = new GsonBuilder()
        .registerTypeAdapterFactory(DefaultMutableTreeNodeTypeAdapter.FACTORY)
        .setPrettyPrinting()
        .create();

下面的DefaultMutableTreeNodeTypeAdapter负责将一个DefaultMutableTreeNode与JSON进行转换。它写入/读取其属性lowsKidsuserObject儿童。不需要写入属性,因为父子关系已经编码在JSON输出的嵌套结构中。

public class DefaultMutableTreeNodeTypeAdapter extends TypeAdapter<DefaultMutableTreeNode> {

    public static final TypeAdapterFactory FACTORY = new TypeAdapterFactory() {

        @Override
        @SuppressWarnings("unchecked") // we use a runtime check to make sure the 'T's equal
        public <T> TypeAdapter<T> create(Gson gson, TypeToken<T> type) {
            if (type.getRawType() == DefaultMutableTreeNode.class) {
                return (TypeAdapter<T>) new DefaultMutableTreeNodeTypeAdapter(gson);
            }
            return null;
        }
    };

    private final Gson gson;

    private DefaultMutableTreeNodeTypeAdapter(Gson gson) {
        this.gson = gson;
    }

    @Override
    public void write(JsonWriter out, DefaultMutableTreeNode node) throws IOException {
        out.beginObject();
        out.name("allowsChildren");
        out.value(node.getAllowsChildren());
        out.name("userObject");
        gson.toJson(node.getUserObject(), Object.class, out);
        if (node.getChildCount() > 0) {
            out.name("children");
            gson.toJson(Collections.list(node.children()), List.class, out); // recursion!
        }
        // No need to write node.getParent(), it would lead to infinite recursion.
        out.endObject();
    }

    @Override
    public DefaultMutableTreeNode read(JsonReader in) throws IOException {
        in.beginObject();
        DefaultMutableTreeNode node = new DefaultMutableTreeNode();
        while (in.hasNext()) {
            switch (in.nextName()) {
            case "allowsChildren":
                node.setAllowsChildren(in.nextBoolean());
                break;
            case "userObject":
                node.setUserObject(gson.fromJson(in, Object.class));
                break;
            case "children":
                in.beginArray();
                while (in.hasNext()) {
                    node.add(read(in)); // recursion!
                    // this did also set the parent of the child-node
                }
                in.endArray();
                break;
            default:
                in.skipValue();
                break;
            }
        }
        in.endObject();
        return node;
    }
}