我想将动态
绑定到动态创建的表。 根据代码,第一个图像是正确的。
下面所示的图像与下面的代码是完美的,
$("#forbtn").click(function()
{
$.ajax({
url: "json/animals.json",
dataType : "json",
type:"post",
success : function(data) {
//console.log(data);
//const myobj = JSON.parse(data);
//console.log(myobj);
var myobj = data;
var tabdata = myobj.length;
var tablebody = '<table border="1" width="100%"><thead><tr><th class="tabhead"> Name </th><th class="tabhead"> Species </th><th class="tabhead"> Foods </th></tr></thead><tbody>';
for (i=0 ; i < myobj.length; i++)
{
tablebody += '<tr>';
tablebody += '<td class="tabdat">';
tablebody += myobj[i].name;
tablebody += '</td>';
tablebody += '<td class="tabdat">';
tablebody += myobj[i].species;
tablebody += '</td>';
tablebody += '<td class="tabdat">'
tablebody += myobj[i].foods;
tablebody += '</td>';
}
tablebody += '</tbody></table>';
$("#table2").html(tablebody);
$("#table2").css({"margin-top" : "10px"});
$("#table2 .tabhead").css({"padding":"5px" , "background-color" : "#E6E6E6"});
$("#table2 .tabdat").css({"padding":"5px" , "background-color" : "#FAFAFA"});
}
});
});
但是,我需要这样的内容,我已经尝试在提到的 下面是json
此代码: 需要重新格式化为: 还有其他方法,例如使用中包含
,但是它给出了for循环的语法错误。 我不明白for循环语法中有什么错误。$.ajax({
url: "json/animals.json",
dataType : "json",
type:"post",
success : function(data) {
//console.log(data);
//const myobj = JSON.parse(data);
//console.log(myobj);
var myobj = data;
var tabdata = myobj.length;
var tablebody = '<table border="1" width="100%"><thead><tr><th class="tabhead"> Name </th><th class="tabhead"> Species </th><th class="tabhead"> Foods </th></tr></thead><tbody>';
for (i=0 ; i < myobj.length; i++)
{
tablebody += '<tr>';
tablebody += '<td class="tabdat">';
tablebody += myobj[i].name;
tablebody += '</td>';
tablebody += '<td class="tabdat">';
tablebody += myobj[i].species;
tablebody += '</td>';
tablebody += '<td class="tabdat">'
'<ul><li>' for(j=0 ; j<myobj[i].foods.likes.length; j++)
{
myobj[i].foods.likes[j];
} '<li></ul>';
tablebody += '</td>';
}
tablebody += '</tbody></table>';
$("#table2").html(tablebody);
$("#table2").css({"margin-top" : "10px"});
$("#table2 .tabhead").css({"padding":"5px" , "background-color" : "#E6E6E6"});
$("#table2 .tabdat").css({"padding":"5px" , "background-color" : "#FAFAFA"});
}
});
[
{
"name": "Meowsy",
"species" : "cat",
"foods": {
"likes": ["tuna", "catnip"]
}
},
{
"name": "Barky",
"species" : "dog",
"foods": {
"likes": ["bones", "carrots"]
}
},
{
"name": "Purrpaws",
"species" : "cat",
"foods": {
"likes": ["mice" , "milk"]
}
}
]
共1个答案
tablebody += '<td class="tabdat">'
'<ul><li>' for(j=0 ; j<myobj[i].foods.likes.length; j++)
{
myobj[i].foods.likes[j];
} '<li></ul>';
tablebody += '<td class="tabdat">';
tablebody += '<ul>';
for (j=0; j < myobj[i].foods.likes.length; j++)
{
tablebody += '<li>' + myobj[i].foods.likes[j] + '</li>';
}
tablebody += '</ul>';
join
,但这说明了如何在字符串concat中添加for循环。相关问题