标题可能不太清楚。我要解释我的问题。
下面是我的代码:
mailchimpMarketing = require("@mailchimp/mailchimp_marketing");
mailchimpMarketing.setConfig({
apiKey: "MY API KEY",
server: "MY SERVER",
});
const getEmailMembersFromList = async (listID, offset , count) => {
const response = await mailchimpMarketing.lists.getListMembersInfo(listID, {offset, count});
emails = response.members.map(member => {
return member.email_address
})
console.log(emails)
}
getEmailMembersFromList("MY LIST ID", 0, 1000)
getEmailMembersFromList("MY LIST ID", 1000, 58)
它在终端上显示两组电子邮件地址。我必须打两个电话，因为有超过1000个电子邮件地址（共1058个）和最大是1000。
现在我想连接这两个数组，可能使用.concat()方法，但我不知道在我的情况下如何实现。
编辑%1
mailchimpMarketing = require("@mailchimp/mailchimp_marketing");
mailchimpMarketing.setConfig({
apiKey: "MY API KEY",
server: "MY SERVER",
});
const getEmailMembersFromList = async (listID, offset , count) => {
const response = await mailchimpMarketing.lists.getListMembersInfo(listID, {offset, count});
emails = response.members.map(member => {
return member.email_address
})
//console.log(emails)
return emails
}
getEmailMembersFromList("MY LIST ID", 0, 1000)
getEmailMembersFromList("MY LIST ID", 1000, 58)
由于async函数总是返回一个promise，因此可以将所有请求添加到一个数组中，并使用promise.all（）获取所有数据。
FYI:您没有从GetEmailMembersFromList函数返回任何使其工作所必需的东西。
示例:
const firstGroup = getEmailMembersFromList("MY LIST ID", 0, 1000);
const secondGroup = getEmailMembersFromList("MY LIST ID", 1000, 58);
Promise.all([firstGroup, secondGroup]).then((values) => {
console.log(values);
});
请尝试以下代码:
let result = [];
const getEmailMembersFromList = async (listID, offset, count) => {
await mailchimpMarketing.lists
.getListMembersInfo(listID, { offset, count })
.then((response) => {
emails = response.members.map((member) => {
return member.email_address;
});
result.concat(emails);
});
};
getEmailMembersFromList("MY LIST ID", 0, 1000);
getEmailMembersFromList("MY LIST ID", 1000, 58);
console.log(result);
