提问者:小点点

使用关联对大容量插入进行序列化


我正在尝试大量插入与关联,我有这个‘歌曲’模型,有一个到多个关系与‘流派’和‘语言’定义的迁移CLI。歌:

module.exports = (sequelize, DataTypes) => {
    class Song extends Model {
     
        static associate(models) {
            // define association here
            Song.hasMany(models["Language"])
            Song.hasMany(models["Genre"])
        }
    };
    Song.init({
        id: {
            type: DataTypes.INTEGER,
            autoIncrement: true,
            primaryKey: true
        },
        name: DataTypes.STRING,
        energy: {type: DataTypes.FLOAT, allowNull: false},
        valence: {type: DataTypes.FLOAT, allowNull: false}
    }, {
        sequelize,
        modelName: 'Song',
        timestamps: true
    });
    return Song;
};

语言:

module.exports = (sequelize, DataTypes) => {
    class Language extends Model {
        static associate(models) {
            // define association here
            models["Language"].belongsTo(models["Song"])
        }
    };
    Language.init({
        id: {
            type: DataTypes.INTEGER,
            autoIncrement: true,
            primaryKey: true
        },
        name: DataTypes.STRING
    }, {
        sequelize,
        modelName: 'Language',
        indexes: [{unique: true, fields: ['name']}]
    });
    return Language;
};

流派:

module.exports = (sequelize, DataTypes) => {
    class Genre extends Model {
        /**
         * Helper method for defining associations.
         * This method is not a part of Sequelize lifecycle.
         * The `models/index` file will call this method automatically.
         */
        static associate(models) {
            // define association here
            models["Genre"].belongsTo(models["Song"])
        }
    };
    Genre.init({
        id: {
            type: DataTypes.INTEGER,
            autoIncrement: true,
            primaryKey: true
        },
        name: DataTypes.STRING
    }, {
        sequelize,
        modelName: 'Genre',
        indexes: [{unique: true, fields: ['name']}]
    });
    return Genre;
};

我正在尝试大量插入具有以下语言和流派的歌曲:

Song.bulkCreate(songs, {
    include: [Genre,Language]
}).then(() => {
    const result = {
        status: "ok",
        message: "Upload Successfully!",
    }
    res.json(result);
});

songs数组中的每首歌曲的结构如下:

{
    name: "abc",
    genres: [{name: "abc"}],
    languages: [{name: "English"}],
    energy:  1,
    valence: 1
}

我的歌表满了,但流派和语言却是空的,我做错了什么?谢了。


共1个答案

匿名用户

不幸的是,BulkCreate不支持与CreateDo类似的Include选项。您应该在事务内部的循环中使用create

const transaction = ...
for (const song of songs) {
  await Song.create(song, {
    include: [Genre,Language]
  }, { transaction })
}
await transaction.commit()

也可以使用promise.all来避免将用于